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For the following reaction, what has been reduced?

[4textCr + 3textO_2 + textH^+ + textOH^- rightarrow 2textCr_2textO_3 + textH_2textO]

a) Chromium (Cr)
b) Oxygen (O_2)
c) Hydrogen ion (H^+)
d) Hydroxide ion (OH^-)

User KSFT
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1 Answer

5 votes

Final answer:

Chromium (Cr) is reduced in the reaction, transitioning to a lower oxidation state in the product chromium(III) oxide (Cr2O3).

Step-by-step explanation:

In the provided reaction, chromium (Cr) is the species that has been reduced. Reduction in chemistry refers to the gain of electrons by a species. Looking at the reaction, chromium starts in an unspecified oxidation state and ends in the chromium(III) oxide (Cr2O3) compound, where it has an oxidation state of +3. This indicates that chromium's oxidation state has decreased, which is the definition of reduction. Furthermore, since oxygen is gaining electrons, it is typically the species being reduced; however, in this reaction, oxygen starts in the O2 molecule with an oxidation state of 0 and ends in the compound Cr2O3, where each oxygen has an oxidation number of -2. Thus, oxygen has not gained electrons in this case, confirming that chromium is the species being reduced.

User MrHetii
by
8.5k points
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