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An 6 kg object accelerating from 17 m/s to 10 m/s. What is the change in momentum of the object?

1 Answer

12 votes

Answer:

Step-by-step explanation:

Comment

It's a deceleration. You are slowing down.

Givens

vi = 17 m/s

vf = 10 ms

m = 6 kg

delta mv = ?

Formula

delta mv = m * (vf - vi)

Solution

delta mv = 6 (10 - 17)

delta mv = 6 ( -7)

delta mv = - 42

User Vijay Angelo
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