Question

The single-phase half-bridge inverter has a resistive load of ( R = 2.4 ) ohms and the DC input voltage is ( V_s = 48 )V. Determine:

(a) The RMS output voltage at the fundamental frequency ( V_textoi ).

(b) The output power.

(c) The average and peak currents of each transistor.

(d) The peak reverse blocking voltage and current of each transistor.

(e) The Total Harmonic Distortion (THD).

(f) The High-Frequency (HF) and Low-Frequency (LOF).

A. (a) ( V_textoi = 24√2 ), (b) Power = 1152W, (c) Avg. current = 12A, Peak current = 16.97A, (d) V_R = 48V, I_R = 16.97A, (e) THD = 0.707%, (f) HF = 500Hz, LOF = 50Hz

B. (a) ( V_textoi = 24 ), (b) Power = 576W, (c) Avg. current = 6A, Peak current = 8.48A, (d) V_R = 24V, I_R = 8.48A, (e) THD = 1.414%, (f) HF = 1000Hz, LOF = 25Hz

C. (a) ( V_textoi = 48√2 ), (b) Power = 2304W, (c) Avg. current = 24A, Peak current = 33.94A, (d) V_R = 96V, I_R = 33.94A, (e) THD = 1%, (f) HF = 100Hz, LOF = 75Hz

D. (a) ( V_textoi = 48 ), (b) Power = 1152W, (c) Avg. current = 12A, Peak current = 16.97A, (d) V_R = 48V, I_R = 16.97A, (e) THD = 2%, (f) HF = 200Hz, LOF = 100Hz

Answer 1

The single-phase half-bridge inverter with a resistive load of 2.4 ohms and a DC input voltage of 48V has an RMS output voltage of 24√2, an output power of 1152W, average current of 12A, peak current of 16.97A, peak reverse blocking voltage of 48V, peak reverse blocking current of 16.97A, a Total Harmonic Distortion (THD) of 0.707%, and a High-Frequency (HF) of 500Hz and a Low-Frequency (LOF) of 50Hz.

Step-by-step explanation:

The RMS output voltage at the fundamental frequency (Voi) is 24√2. The output power is 1152W. The average current of each transistor is 12A and the peak current is 16.97A. The peak reverse blocking voltage of each transistor is 48V and the peak reverse blocking current is 16.97A. The Total Harmonic Distortion (THD) is 0.707%. The High-Frequency (HF) is 500Hz and the Low-Frequency (LOF) is 50Hz.