Question

A bus is moving with the initial velocity 10m/s. After 2 seconds, the velocity becomes 20m/s. Find the acceleration and distance moved by the bus.

a) Acceleration = 5 m/s², Distance = 25 m
b) Acceleration = 10 m/s², Distance = 20 m
c) Acceleration = 5 m/s², Distance = 20 m
d) Acceleration = 10 m/s², Distance = 25 m

Answer 1

The acceleration of the bus is 10 m/s² and the distance moved by the bus is 100 m.

Step-by-step explanation:

To find the acceleration, we use the formula: acceleration = (change in velocity) / (time taken). In this case, the change in velocity is 20 m/s - 10 m/s = 10 m/s, and the time taken is 2 seconds. Thus, the acceleration is 10 m/s².

To find the distance moved by the bus, we can use the formula: distance = initial velocity × time + 0.5 × acceleration × time². Substituting in the values, we get: distance = 10 m/s × 2 s + 0.5 × 10 m/s² × (2 s)² = 20 m + 0.5 × 10 m/s² × 4 s² = 20 m + 0.5 × 10 m/s² × 16 s = 20 m + 0.5 × 160 m = 20 m + 80 m = 100 m.