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A spinner has 12 equal sectors with different letters for each sector, as example Hamlet spins the spinner 5 times, and it stops at the letter B 4 times. If he spins the spinner a 6th time, what is the theoretical probability that this time it will stop at the letter B?

A.) 1/12
B.) 1/10
C.) 1/5
D.) 1/4

User Pion
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Final answer:

The theoretical probability of Hamlet's spinner stopping at the letter B on the sixth spin is 1/12, since there are 12 equal sectors, each representing an equal chance of being landed on per spin.

Step-by-step explanation:

The question is about calculating the theoretical probability of landing on a specific letter ('B') on the sixth spin of a spinner that has 12 equal sectors, each with a different letter. Since the spinner has 12 equal sectors and is assumed to be fair (not biased), the probability of landing on any given letter is the same for every spin, regardless of previous outcomes. The probability is calculated using the simple formula:

Probability = (Number of favorable outcomes) / (Total number of possible outcomes)

Since there is only one 'B' on the spinner and there are 12 equal sectors, the probability of landing on 'B' for any given spin is 1/12, represented as:

Probability of landing on B = 1 / 12

The previous spins do not affect the outcome of the following spins, so the probability remains the same for the sixth spin.

User Pawel Laskowski
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