Final answer:
The probability of getting more than one tail when tossing a coin four times is calculated as the complementary event of getting at most one tail. After determining there are 5 ways to achieve at most one tail out of 16 possible outcomes, the probability of the complementary event is found to be 11/16.
Step-by-step explanation:
The question revolves around calculating the probability of getting more than one tail when a coin is tossed four times. Each coin toss has two possible outcomes: heads (H) or tails (T), and each outcome is equally likely. The total number of possible outcomes for four coin tosses is 24, which is 16, since each toss is independent of the others.
To find the probability of getting more than one tail, we consider the complementary event: getting 0 or 1 tail and then subtracting from 1. There is 1 way to get 0 tails (HHHH) and 4 ways to get 1 tail (THHH, HTHH, HHTH, HHHT). So in total, there are 1 + 4 = 5 ways to get at most one tail. The probability of getting at most one tail is therefore 5/16 because there are 16 possible outcomes. To find the probability of the complementary event, which is getting more than one tail, we subtract the probability of at most one tail from 1:
Probability of more than one tail = 1 - Probability of at most one tail = 1 - (5/16) = (16/16) - (5/16) = 11/16.
Thus, the correct answer is b) 11/16.