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Reading on an ammeter is 3.5A. How much charge passes through the light bulb in 120 seconds?

a. 420 C

b. 210 C

c. 250 C

d. 150 C

User Vignajeth
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7.6k points

2 Answers

4 votes

Answer:

The formula relating current (I) and charge (Q) is:

\[ Q = I \times t \]

Where:

- \( Q \) is the charge in coulombs (C),

- \( I \) is the current in amperes (A), and

- \( t \) is the time in seconds (s).

Given that the current is \( 3.5 \, \text{A} \) and the time is \( 120 \, \text{s} \), you can substitute these values into the formula:

\[ Q = 3.5 \, \text{A} \times 120 \, \text{s} \]

Now, calculate the charge:

\[ Q = 420 \, \text{C} \]

So, the answer is:

a. 420 C

User Woppi
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8.4k points
4 votes

Final answer:

The charge passed through the light bulb in 120 seconds is 420C.

Step-by-step explanation:

To calculate the charge passed through a circuit, we use the formula: charge (Q) = current (I) * time (t). In this case, the current reading on the ammeter is 3.5A and the time is 120 seconds. Therefore, the charge passed through the light bulb is 3.5A * 120s = 420C.

User Patrys
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7.7k points