Final answer:
To calculate the mass of water that could be melted at 0°C if 985 kJ of heat were absorbed by the water, we can use the equation Q = m × ΔHf, where Q is the heat absorbed, m is the mass of water, and ΔHf is the heat of fusion for water. The heat of fusion for water is 334 J/g. Rearranging the equation, we find that m = Q ÷ ΔHf. Substituting the values, m = 985 kJ ÷ (334 J/g) = 2942.51 g. Therefore, the mass of water that could be melted is approximately 2942.51 grams.
Step-by-step explanation:
To calculate the mass of water that could be melted at 0°C if 985 kJ of heat were absorbed by the water, we can use the equation Q = m × ΔHf, where Q is the heat absorbed, m is the mass of water, and ΔHf is the heat of fusion for water. The heat of fusion for water is 334 J/g. Rearranging the equation, we find that m = Q ÷ ΔHf. Substituting the values, m = 985 kJ ÷ (334 J/g) = 2942.51 g. Therefore, the mass of water that could be melted is approximately 2942.51 grams.