Question

A charge of (4.5 × 10⁻⁹) is located 3.2m from a charge of (-2.8 × 10⁻¹⁰). Find the electrostatic force exerted on the charge on the other.

a) (2.304 × 10⁻⁹) N
b) (6.4 × 10⁻¹⁹) N
c) (1.44 × 10⁻¹⁸) N
d) (7.68 × 10⁻¹⁸) N

Answer 1

The electrostatic force exerted on the charge can be calculated using Coulomb's Law. Plugging the given values into the equation gives us a force of (7.68 × 10⁻¹⁸) N.

Step-by-step explanation:

The electrostatic force exerted on the charge can be calculated using Coulomb's Law. According to Coulomb's Law, the force between two charges is given by the equation:

F = k(q1 * q2) / r^2

Where F is the force, k is the electrostatic constant (approximately 8.99 x 10^9 N·m²/C²), q1 and q2 are the charges, and r is the distance between the charges.

In this case, q1 = 4.5 × 10⁻⁹ C, q2 = -2.8 × 10⁻¹⁰ C, and r = 3.2 m. Plugging these values into the equation, we get:

F = (8.99 x 10^9 N·m²/C²) * ((4.5 × 10⁻⁹ C) * (-2.8 × 10⁻¹⁰ C)) / (3.2 m)^2

Calculating this expression gives us the answer, which is (7.68 × 10⁻¹⁸) N. Therefore, the correct answer is option d) (7.68 × 10⁻¹⁸) N.