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Tim Worker is doing his budget. He discovers that the average electric bill for the year was $206.00 with a standard deviation of $10.00. What percent of his expenses in this category would he expect to fall between $184.00 and $200.00?

The z for $184.00 =
A:-.6
B:48.6
C: 26
D: 2.2
E: 22.6
The percent of area associated with $184.00 =
A: 2.2
B: .6
C: 26
D: 22.6
E: 48.6
The z for $200.00 = -
A: .6
B: 48.6
C: 22.6
D: 26
E: 2.2
The percent of area associated with $200.00 =
A: 48.6
B: 2.2
C: 22.6
D: 26
E: .6
Subtracting the two percentages, the percent of expenses between $184.00 and $200.00 is
A 22.6
B 48.6
C .6
D 2.2
E 26

1 Answer

2 votes

Final answer:

To find the percent of expenses that Tim would expect to fall between $184.00 and $200.00, calculate the z-scores and corresponding percentages using the normal distribution table. The percent of expenses between $184.00 and $200.00 is 26%.

Step-by-step explanation:

To find the percent of expenses that Tim would expect to fall between $184.00 and $200.00, we need to calculate the z-scores for those values and then find the corresponding percentages using the normal distribution table.

The z-score for $184.00 is -0.6. Looking up the z-score in the table, we find that the associated percentage is 22.6%. The z-score for $200.00 is 0.6, and the associated percentage is 48.6%.

To find the percent of expenses between $184.00 and $200.00, we subtract the percentage associated with $184.00 from the percentage associated with $200.00. So, the percent of expenses between $184.00 and $200.00 is 48.6% - 22.6% = 26%.

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