Question

An airplane starts from rest and undergoes a uniform acceleration of 11.7 m/s² for 23.6 seconds before leaving the ground. What is its displacement?

a) 276.12 m
b) 138.06 m
c) 553.44 m
d) 415.80 m

Answer 1

The displacement of the airplane is 138.06 m.

Step-by-step explanation:

To find the displacement of the airplane, we can use the equation:

displacement = initial velocity * time + (1/2) * acceleration * time^2

Since the airplane starts from rest, the initial velocity is 0. The acceleration is 11.7 m/s² and the time is 23.6 seconds.

Plugging in these values into the equation, we get:

displacement = 0 * 23.6 + (1/2) * 11.7 * 23.6^2 = 138.06 m

Therefore, the airplane's displacement is 138.06 m.