Question

A metal pellet with a mass of 100.0 g, originally at 95°C, is dropped into a 218 g sample of water, initially at 23.8°C. Calculate the final temperature of the water and pellet. The specific heat of water is 4.184 J/g.°C. The specific heat of the pellet is 0.568 J/g.°C.

A. 28.0 C
B. 72.0 C
C. 95.0 C
D. 41.3 C
E. 23.8 C

Answer 1

The final temperature of the water and pellet is 41.3°C.

Step-by-step explanation:

To calculate the final temperature of the water and pellet, we can use the principle of heat transfer. The heat lost by the pellet is equal to the heat gained by the water. We can calculate the heat lost by the pellet using the equation Q = m * c * ΔT, where Q is the heat lost, m is the mass of the pellet, c is the specific heat capacity of the pellet, and ΔT is the change in temperature.

Heat gained by the water can be calculated using the equation Q = m * c * ΔT, where m is the mass of the water, c is the specific heat capacity of the water, and ΔT is the change in temperature.

Equating the two equations and solving for the final temperature gives us a final temperature of 41.3°C (Choice D).