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On a coordinate plane, a piecewise function has three lines. What is the domain indicated on the graph for each portion of the piecewise function?

1st piece:
A. (f(x) = -2), Domain: ((-9, 0))
B. (f(x) = 2x + 1), Domain: ((-9, 0))
2nd piece:
A. (f(x) = -2), Domain: ((0, 4))
B. (f(x) = 2x + 1), Domain: ((0, 4))
3rd piece:
A. (f(x) = -2), Domain: ((4, 8))
B. (f(x) = 2x + 1), Domain: ((4, 8))

1 Answer

5 votes

Final answer:

The domain of each portion of the piecewise function indicates the x-values over which each part is defined. For the first piece, the domains given are for intervals (-9, 0), for the second piece, domains are for (0, 4), and for the third piece, domains are for (4, 8).

Step-by-step explanation:

In Mathematics, particularly when dealing with piecewise functions on a coordinate plane, the domain of each piece of the function refers to the set of all input values (x-values) over which the function is defined. In this case, each portion of the piecewise function is defined for a specific interval of x-values.

For the first piece, if f(x) = -2 is a horizontal line, the domain represents the x-values over which this constant line exists. According to (B), for the line f(x) = 2x + 1, its domain from the interval (-9, 0) suggests that it is defined from just left of x=-9 to just before x=0, likely indicating an open interval where -9 and 0 are not included.

Similarly, for the second piece, the provided domains for f(x) = -2 and f(x) = 2x + 1 within the interval (0, 4) imply that these lines or functions are defined from just after x=0 to just before x=4.

The third piece follows the same premise, whereby the functions f(x) = -2 and f(x) = 2x + 1 have domains in the interval (4, 8), meaning they apply from just after x=4 to just before x=8.

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