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If you invest $1000 for 6 years at 10.5%, compounded every 4 months, how much would it be worth?

a. $1,708.15
b. $1,825.90
c. $1,946.08
d. $2,069.73

1 Answer

6 votes

Final answer:

After 6 years, a $1000 investment at a 10.5% interest rate compounded every 4 months would grow to $1,946.08, demonstrating the impact of compound interest on investments over time.

Step-by-step explanation:

To calculate the future value of an investment with compound interest, we can use the formula:

A = P(1 + r/n)^(nt)

Where:

  • A is the amount of money accumulated after n years, including interest.
  • P is the principal amount (the initial amount of money).
  • r is the annual interest rate (decimal).
  • n is the number of times that interest is compounded per year.
  • t is the time the money is invested for, in years.

In this case, P is $1000, r is 10.5% or 0.105, n is 3 (since interest is compounded every 4 months, or three times a year), and t is 6 years.

Plugging in the values we get:

A = 1000(1 + 0.105/3)^(3*6)

A = 1000(1 + 0.035)^(18)

A = 1000(1.035)^18

A = 1000 * 1.94608

A = $1,946.08

Therefore, after 6 years, $1000 invested at 10.5% interest compounded every 4 months would be worth $1,946.08.

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