Question

How would you make 100 mL of a 0.10 N solution of potassium hydroxide (KOH) in water, where the molecular weight of KOH is 56 g/mol?

A) Dissolve 0.10 g of KOH in 100 mL of water.
B) Dissolve 5.6 g of KOH in 100 mL of water.
C) Dissolve 10 g of KOH in 100 mL of water.
D) Dissolve 56 g of KOH in 100 mL of water.

Answer 1

To make a 0.10 N solution of potassium hydroxide (KOH) in water, you need to dissolve 5.6 g of KOH in 100 mL of water.

Step-by-step explanation:

To make a 0.10 N solution of potassium hydroxide (KOH) in water, you need to dissolve a specific amount of KOH in a specific volume of water. The equation for finding the number of moles (N) is N = concentration (M) x volume (L). In this case, the desired concentration is 0.10 N and the desired volume is 100 mL. So, to find the amount of KOH needed, you can rearrange the equation as mass (g) = moles (N) x molecular weight (g/mol).

Using the given molecular weight of KOH as 56 g/mol, and the desired volume as 100 mL, the correct option would be B) Dissolve 5.6 g of KOH in 100 mL of water.