Question

CsBr has cubic structure with edge length 4.3 Å (unit is armstrong). The shortest interionic distance between Cs⁺ and Br⁻ is?

a) 4.3 Å
b) 8.6 Å
c) 2.15 Å
d) 6.07 Å

Answer 1

The shortest interionic distance between Cs+ and Br- ions in CsBr is 8.6 Å.

Step-by-step explanation:

The shortest interionic distance between Cs+ and Br- in CsBr can be determined by considering the structure of the crystal. CsBr has a cubic structure, meaning it forms a cube with Cs+ ions at the corners and Br- ions at the center of the faces. The edge length of the cube is given as 4.3 Å. To find the shortest interionic distance, we can draw a diagonal across the face of the cube. This diagonal is equal to twice the edge length of the cube. Therefore, the shortest interionic distance is 2 times the edge length, which is 2 x 4.3 Å = 8.6 Å.