Final answer:
The amount of SO2 produced from burning coal containing 330.92 g of FeS2 is approximately 705.4 g.
Step-by-step explanation:
To determine the amount of SO2 produced, we need to calculate the moles of FeS2 and use the stoichiometry of the balanced equation to find the moles of SO2.
Molar mass of FeS2 = 119.98 g/mol
Moles of FeS2 = mass / molar mass = 330.92 g / 119.98 g/mol = 2.754 mol
From the stoichiometry of the balanced equation, 1 mole of FeS2 produces 8 moles of SO2:
2 FeS2 + 11 O2 → 2 Fe2O3 + 8 SO2
Therefore, the moles of SO2 produced = 2.754 mol FeS2 * (8 mol SO2 / 2 mol FeS2) = 11.016 mol
Converting moles to grams:
Mass of SO2 = moles * molar mass = 11.016 mol * 64.06 g/mol = 705.437 g
Rounded to one decimal place, the amount of SO2 produced is approximately 705.4 g.