Question

The half-life of mathium is 23 days.

a) Write an equation that models the mass of mathium remaining over time.
b) Determine the number of days it would take for there to be 1.05g of mathium left.

Answer 1

The equation that models the mass of mathium remaining over time is given by mass remaining = initial mass × (1/2)^(time / half-life). To determine the number of days it would take for there to be 1.05g of mathium left, you can rearrange the equation and solve for time using time = half-life × log(1/2)(mass remaining / initial mass).

Step-by-step explanation:

The equation that models the mass of mathium remaining over time can be written as:

mass remaining = initial mass × (1/2)(time / half-life)

To determine the number of days it would take for there to be 1.05g of mathium left, you can rearrange the equation and solve for time:

time = half-life × log(1/2)(mass remaining / initial mass)

Plugging in the values, we get: time = 23 days × log(1/2)(1.05g / initial mass)