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What amount of gasoline (in liters) does a gasoline engine, having an efficiency of 0.40 and generating 1800 W of power, consume per hour, considering that a liter of gasoline contains an energy content of 3.7 × 10⁷ J?

A) 0.121 liters
B) 0.486 liters
C) 1.215 liters
D) 4.86 liters

User Klasik
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1 Answer

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Final answer:

The amount of gasoline consumed by a gasoline engine can be calculated using the formula Gasoline Consumption = (Power Generated / Efficiency) / Energy Content of Gasoline. Plugging in the given values, the gasoline consumption per hour is approximately 0.121 liters.

Step-by-step explanation:

To calculate the amount of gasoline consumed per hour by a gasoline engine, we need to use the formula:

Gasoline Consumption = (Power Generated / Efficiency) / Energy Content of Gasoline

Given that the engine has an efficiency of 0.40 and generates 1800 W of power, and a liter of gasoline contains an energy content of 3.7 × 10⁷ J, we can plug in these values:

Gasoline Consumption = (1800 / 0.40) / (3.7 × 10⁷)

Simplifying the equation, we get:

Gasoline Consumption = 4500 / (3.7 × 10⁷)

Dividing 4500 by 3.7 × 10⁷, we find that the gasoline consumption per hour is approximately 0.121 liters. Therefore, the correct answer is A) 0.121 liters.

User Kirill
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