Question

How can the ions Ag⁺(aq), Ba²⁺(aq), and Al³⁺(aq) in a 0.1 M concentration solution be separated from each other and from the solution using a procedure based on solubility tables? Outline the step-by-step order of separation.

Answer 1

To separate the ions Ag⁺(aq), Ba²⁺(aq), and Al³⁺(aq) in a 0.1 M concentration solution, you can use a procedure based on solubility tables. The step-by-step order of separation is to react Al³⁺(aq) with dilute HCl, then Ba²⁺(aq) with dilute NaOH, and finally Ag⁺(aq) with dilute H₂SO₄.

Step-by-step explanation:

To separate the ions Ag⁺(aq), Ba²⁺(aq), and Al³⁺(aq) in a 0.1 M concentration solution, we can use a procedure based on solubility tables. Here are the step-by-step order of separation:

1. First, add a few drops of dilute HCl to the solution. This will react with Al³⁺(aq) to form AlCl₃, which is soluble.
2. Next, add a few drops of dilute NaOH to the solution. This will react with Ba²⁺(aq) to form Ba(OH)₂, which is insoluble and will precipitate out.
3. Finally, add a few drops of dilute H₂SO₄ to the solution. This will react with Ag⁺(aq) to form Ag₂SO₄, which is insoluble and will precipitate out.

By following this procedure, we can separate the ions Ag⁺(aq), Ba²⁺(aq), and Al³⁺(aq) from each other and from the solution.