Final answer:
To determine the head of air equivalent to a pressure of 75 mm of water, we can use the formula for the height of a column of fluid. The height is calculated to be approximately 60.98 meters.
Step-by-step explanation:
To determine the head of air equivalent to a pressure of 75 mm of water, we need to calculate the height of a column of air with the same pressure. The formula to calculate the height of a column of fluid is:
where pressure is the given pressure, density is the density of air, and g is the acceleration due to gravity. Using the given values:
pressure = 75 mm H2O = 9.81 × 75 Pa = 735.75 Pa
density of air = 1.20 kg/m³
g = 9.81 m/s²
Substituting the values into the formula:
height = (735.75 / 1.20) / 9.81 ≈ 60.98 meters
Therefore, the head of air equivalent to a pressure of 75 mm of water is approximately 60.98 meters.