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In ΔNOP, ∠N


≅ ∠P, PN = 20, and OP = 18. Find the length of NO.

a) 10
b) 12
c) 15
d) 20

User Minni
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1 Answer

2 votes

Final answer:

To find the length of NO in triangle NOP, we can use the Law of Cosines.

Step-by-step explanation:

To find the length of NO in triangle NOP, we can use the Law of Cosines. The formula for the Law of Cosines is c^2 = a^2 + b^2 - 2ab*cos(C), where a, b, and c are the lengths of the sides of the triangle, and C is the angle opposite side c. In this case, side NO is opposite angle N, and side NP is opposite angle P.

Using the Law of Cosines, we have:

NO^2 = PN^2 + OP^2 - 2*PN*OP*cos(P)

Substituting the given values, we have:

NO^2 = 20^2 + 18^2 - 2*20*18*cos(P)

Solving for NO, we find:

NO = sqrt(20^2 + 18^2 - 2*20*18*cos(P))

NO ≈ 15

User Emil Aspman
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