Question

A ball hits a wall horizontally at 8 m/s. It rebounds horizontally at 6 m/s. The ball is in contact with the wall for 0.02 s. What is the acceleration of the ball?

(A) 100 m/s²
(B) 200 m/s²
(C) -100 m/s²
(D) -200 m/s²

Answer 1

The acceleration of the ball is -700 m/s², so the correct answer is (D) -200 m/s².

Step-by-step explanation:

The acceleration of the ball can be found using the equation:

a = (vf - vi) / t

Where:

a is the acceleration,

vf is the final velocity,

vi is the initial velocity,

and t is the time.

In this case, the initial velocity of the ball is 8 m/s and the final velocity is -6 m/s (since it rebounds in the opposite direction).

Substituting these values into the equation:

a = (-6 m/s - 8 m/s) / 0.02 s

a = -14 m/s / 0.02 s

a = -700 m/s²

The acceleration of the ball is -700 m/s², so the correct answer is (D) -200 m/s².