Final answer:
The molarity of the solution containing 230 grams of ethanol dissolved in 500 grams of water is approximately 6.84 M.
Step-by-step explanation:
To determine the molarity of the solution, we need to calculate the number of moles of ethanol and the volume of the solution. The molarity (M) is defined as the number of moles of solute per liter of solution. Using the given information, we first calculate the number of moles of ethanol by dividing the mass of ethanol (230 g) by its molar mass (46.07 g/mol). This gives us approximately 4.99 moles of ethanol. Next, we calculate the volume of the solution by adding the mass of ethanol (230 g) to the mass of water (500 g) to get a total mass of 730 g. Since the density of water is approximately 1 g/mL, the volume of the solution is 730 mL.
To convert the volume to liters, we divide it by 1000, giving us 0.73 L. Finally, we can calculate the molarity by dividing the number of moles of ethanol (4.99 mol) by the volume of the solution in liters (0.73 L). This gives us approximately 6.84 M. Therefore, the molarity of the solution is approximately 6.84 M.