Question

Given the following reactions:

(CaCO₃ (s) → CaO (s) + CO₂ (g)) ΔH = 178.1 kJ
(C (s, graphite) + O₂(g) → CO₂(g)) ΔH = -393.5 kJ
The enthalpy of the reaction (CaCO₃ (s) → CaO (s) + C (s, graphite) + O₂ (g)) is _______ₖJ.
A) -215.4
B) 215.4
C) 7.01 × 10⁴
D) 571.6
E) -571.6

Answer 1

The enthalpy of the reaction (CaCO₃ (s) → CaO (s) + C (s, graphite) + O₂ (g)) is -215.4 kJ.

Step-by-step explanation:

The enthalpy of the reaction (CaCO₃ (s) → CaO (s) + C (s, graphite) + O₂ (g)) can be calculated by determining the sum of the enthalpies of the individual reactions.

Given that the enthalpy change for the reaction CaCO₃ (s) → CaO (s) + CO₂ (g) is 178.1 kJ and the enthalpy change for the reaction C (s, graphite) + O₂ (g) → CO₂ (g) is -393.5 kJ, we can add these two values to find the enthalpy change for the overall reaction:

ΔH = 178.1 kJ + (-393.5 kJ) = -215.4 kJ

Therefore, the enthalpy of the reaction (CaCO₃ (s) → CaO (s) + C (s, graphite) + O₂ (g)) is -215.4 kJ.