Question

River's chemistry class is doing an experiment in which the students create a 3096 hydrochloric

acid mixture by mixing a certain amount of 25% solution with a different amount of 5096
solution. The amount of 25% solution used is 20 liters less than 5 times the amount of 5096
solution used. How much of the 25% solution and the 50% solution are needed in all?
A 30 liters, 10 liters
B 80 liters, 20 liters
C 130 liters, 30 liters
D 50 liters, 40 liters

Answer 1

To find the amount of each solution needed, we can set up an equation and solve for x.

Step-by-step explanation:

Let the amount of 50% solution used be x liters.

The amount of 25% solution used is 5 times the amount of 50% solution used, minus 20 liters. So it is 5x - 20 liters.

The total amount of solution is 3096 liters, so we can set up the equation: x + (5x - 20) = 3096.

Simplifying the equation, we get 6x - 20 = 3096. Solving for x, we find that x = 516 liters.

Therefore, the amount of 50% solution needed is 516 liters, and the amount of 25% solution needed is 5x - 20 = 5(516) - 20 = 2576 liters.