Question

If a 0.075 L solution contains 9 grams of ZnSO₄, what is the molarity?

a. 0.2 M
b. 0.4 M
c. 0.6 M
d. 0.8 M

Answer 1

To find the molarity of the solution, divide the number of moles of ZnSO₄ by the volume of the solution in liters. In this case, the molarity is 0.743 M.

Step-by-step explanation:

To calculate the molarity of a solution, we need to know the amount of solute in grams and the volume of the solution in liters. In this case, we have a 0.075 L solution containing 9 grams of ZnSO₄. To find the molarity, we divide the number of moles of ZnSO₄ by the volume of the solution in liters.

First, we convert the mass of ZnSO₄ to moles using its molar mass (161.47 g/mol). 9 g / 161.47 g/mol = 0.0557 mol.

Then, we divide the number of moles by the volume of the solution in liters: 0.0557 mol / 0.075 L = 0.743 M.

Therefore, the molarity of the solution is 0.743 M.