Final answer:
The calculated effect size using Cohen's d is 0.69, indicating that the mean self-esteem of participating youths is moderately higher than the general youth population.
The correct answer is A.
Step-by-step explanation:
To calculate the effect size for the mean difference in self-esteem between youths who participate in cultural and sports activities and the general youth population, we can use Cohen's d formula, which is:
d = (M1 - M2) / SDpooled
Where:
- M1 is the mean self-esteem score for participating youths, which is 53.8.
- M2 is the mean self-esteem score for the general population of youths, which is 50.
- SDpooled is the pooled standard deviation, which can be calculated as the square root of the average of the squared standard deviations since the sample sizes are equal.
First, we need to calculate the pooled standard deviation:
SDpooled = √[(SD1^2 + SD2^2) / 2] = √[(5.1^2 + 5.9^2) / 2] = √[(26.01 + 34.81) / 2] = √[30.41] ≈ 5.51
Now we can calculate the effect size:
d = (53.8 - 50) / 5.51 ≈ 0.69
Since the Cohen's d effect size is 0.69, it falls between the medium (0.5) and large (0.8) effect sizes by Cohen's standard, suggesting that the mean self-esteem of participating youths is moderately higher than the general youth population. Therefore, option a) is the correct interpretation of the effect size.