8.5k views
2 votes
Solve (3² - 1 - 12 ⋅ 3ˣ⁺⁸¹ = 0) with proper steps and explanation.

User Hkasera
by
8.0k points

1 Answer

6 votes

Final answer:

To solve the equation (3² - 1 - 12 ⋅ 3ˣ⁺⁸¹ = 0), you can simplify and rewrite it as a quadratic equation. Then, divide both sides by -12 and take the logarithm of both sides. Finally, calculate the logarithms to find x ≈ -80.74.

Step-by-step explanation:

To solve the equation (3² - 1 - 12 ⋅ 3ˣ⁺⁸¹ = 0), we first simplify and rewrite it as a quadratic equation:

9 - 1 - 12⋅3ˣ⁺⁸¹ = 0

8 - 12⋅3ˣ⁺⁸¹ = 0

-12⋅3ˣ⁺⁸¹ = -8

Dividing both sides by -12, we get:

3ˣ⁺⁸¹ = 8/12

3ˣ⁺⁸¹ = 2/3

Taking the logarithm of both sides, we have:

(x+81)log(3) = log(2/3)

x+81 = log(2/3)/log(3)

x = log(2/3)/log(3) - 81

Calculating the logarithms, we find that x ≈ -80.74.

User Lorenzo Polidori
by
7.8k points