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An oil tank has a base of area 2.5 m² and is filled with oil to a depth of 1.2m. The density of the oil is 800 kg/ m³. What is the force exerted on the base of the tank due to the oil?

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Final answer:

To calculate the force exerted on the base of the tank due to the oil, multiply the weight of the oil by the acceleration due to gravity. The weight can be calculated by multiplying the mass of the oil by the acceleration due to gravity. The mass can be found by multiplying the density of the oil by its volume.

Step-by-step explanation:

To calculate the force exerted on the base of the tank due to the oil, we need to determine the weight of the oil. Weight is equal to the mass of an object multiplied by the acceleration due to gravity. In this case, the mass of the oil can be found by multiplying the density of the oil by its volume. The volume of the oil can be calculated by multiplying the area of the base of the tank by the depth of the oil. Finally, the force can be calculated by multiplying the weight of the oil by the acceleration due to gravity.



Weight = mass * acceleration due to gravity



Mass = density * volume



Volume = area * depth



Force = weight * acceleration due to gravity



Substituting the given values, we have:

Density = 800 kg/m³,
Area = 2.5 m²,
Depth = 1.2 m,
Acceleration due to gravity = 9.8 m/s².



Plugging these values into the equations, we get:



Volume = 2.5 m² * 1.2 m = 3 m³



Mass = 800 kg/m³ * 3 m³ = 2400 kg



Weight = 2400 kg * 9.8 m/s² = 23520 N



Force = 23520 N * 9.8 m/s² = 230016 N



Therefore, the force exerted on the base of the tank due to the oil is 230016 Newtons.

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