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Larry drives 200 miles to a convention and then back home using the same route. If the speed coming home was 10 mph slower, due to weather, and if the total driving time is 9 hours for the entire trip, how fast did he drive in each direction?

a) 50 mph there, 40 mph back
b) 60 mph there, 50 mph back
c) 55 mph there, 45 mph back
d) 45 mph there, 35 mph back

User L Tyrone
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1 Answer

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Final answer:

Larry drove 50 mph to the convention and 40 mph back home. The total drive time was 9 hours, and by setting up the equation with speeds and distances, and then solving for x, we can determine the speeds in each direction.

Step-by-step explanation:

To solve for Larry's speed in each direction, we use the formula distance = speed × time. Let's denote the speed on the way there as x mph and the speed on the way back as x - 10 mph. Since the distance in each direction is 200 miles, the time taken to travel to the convention is 200/x hours, and the time taken to travel back is 200/(x - 10) hours. The total driving time given is 9 hours, so we can set up the equation:

200/x + 200/(x - 10) = 9.

To solve this equation, we find a common denominator and solve for x. After simplifying, we get:

200(x - 10) + 200x = 9x(x - 10)

200x - 2000 + 200x = 9x^2 - 90x

400x - 2000 = 9x^2 - 90x

9x^2 - 490x + 2000 = 0

Using the quadratic formula or factoring, we find that x = 50 mph is a suitable solution (the other solution being negative and thus non-physical). Therefore, Larry drove 50 mph to the convention and 40 mph back home. The correct answer is (a) 50 mph there, 40 mph back.

User Justin Weiss
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