Final answer:
To solve for the system of equations (8x - 10y = -23) and (9x + 10y = -16), we add the equations to eliminate the y-term and solve for x. Then, we substitute x back into one of the equations to find y. The approximate solution is (-2.3, 0.5).
Step-by-step explanation:
The student is trying to solve a system of two linear equations, namely (8x - 10y = -23) and (9x + 10y = -16). To find the approximate solution for this system, we can add these two equations together, which will eliminate the y-term, allowing us to solve for x. Once we have solved for x, we can substitute the value of x into either of the original equations to find the corresponding y-value.
The addition of the two equations gives us:
- 8x - 10y + 9x + 10y = -23 - 16
- 17x = -39
- x = -39 / 17
- x = -2.294
Approximating x to one decimal place gives us x = -2.3. To find y, we substitute x back into the first original equation:
- 8(-2.3) - 10y = -23
- -18.4 - 10y = -23
- -10y = -23 + 18.4
- -10y = -4.6
- y = -4.6 / -10
- y = 0.46
Approximating y to one decimal place gives us y = 0.5. Therefore, the approximate solution for the system is x = -2.3 and y = 0.5, which corresponds to option a) (-2.3, 0.5).