Question

An elastic wire was vertically suspended by a metallic ball of mass 6000g. Calculate its extension provided the constant of proportionality is 1.2 N/m.

a) 0.005 m
b) 0.04 m
c) 0.1 m
d) 0.2 m

Answer 1

The extension of the elastic wire is approximately 0.049m.

Step-by-step explanation:

To calculate the extension of the elastic wire, we can use Hooke's Law, which states that the extension of an elastic material is proportional to the applied force. The formula for Hooke's Law is given by:

F = kx

Where F is the applied force, k is the constant of proportionality or the spring constant, and x is the extension.

In this case, the mass of the metallic ball is 6000g, which is equivalent to 6kg. And the constant of proportionality is given as 1.2 N/m. Substituting these values into the equation, we can solve for the extension:

F = kx

6kg × 9.8 m/s² = 1.2 N/m × x

x = (6kg × 9.8 m/s²) / (1.2 N/m) ≈ 49.0m

Therefore, the extension of the wire is approximately 0.049m.