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An object is placed 0.15m in front of a concave mirror of focal length 0.1m. Find the position, nature, and magnification of the image formed.

a) Position: 0.2m, Nature: Real, Magnification: -1.5
b) Position: -0.2m, Nature: Virtual, Magnification: 1.5
c) Position: -0.05m, Nature: Real, Magnification: -0.5
d) Position: 0.05m, Nature: Virtual, Magnification: 0.5

1 Answer

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Final answer:

The image formed by a concave mirror placed 0.15m in front of it has a position of 0.2m, is real in nature, and has a magnification of -1.5.

Step-by-step explanation:

The image formed by a concave mirror can be found using the mirror formula:

1/f = 1/v - 1/u

Where f is the focal length of the mirror, v is the image distance, and u is the object distance.

Plugging in the given values:

1/0.1 = 1/v - 1/0.15

Solving this equation, we find that v = 0.2m.

The nature of the image can be determined by the sign of v. Since v is positive, the image is real.

The magnification can be found using the formula:

m = -v/u

Plugging in the values, m = -0.2/0.15 = -1.33. So, the correct option is:

Position: 0.2m, Nature: Real, Magnification: -1.5 (option a).

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