Question

Determine the coordinates of the points R&S, then find the length of RS. Determine the length of PQ.

a) (R(0, 0), S(6, 0), RS = 6), (P(2, 3), Q(6, 3), PQ = 4)
b) (R(0, 0), S(6, 0), RS = 8), (P(2, 3), Q(6, 3), PQ = 4)
c) (R(2, 2), S(8, 2), RS = 6), (P(0, 4), Q(6, 4), PQ = 6)
d) (R(2, 2), S(8, 2), RS = 8), (P(0, 4), Q(6, 4), PQ = 6)

Answer 1

The coordinates of points R and S are (0, 0) and (6, 0) respectively. The length of RS is 6. The length of PQ is 4.

Step-by-step explanation:

For part (a), the coordinates of points R and S are R(0, 0) and S(6, 0) respectively. The length of RS can be found using the distance formula, which is √((6-0)^2 + (0-0)^2) = √(36) = 6.

For part (b), the coordinates of points R and S are R(0, 0) and S(6, 0) respectively. The length of RS is given as RS = 8. However, using the distance formula, we find that RS is actually √((6-0)^2 + (0-0)^2) = √(36) = 6. So the given length is incorrect.

The length of PQ can be found using the distance formula as well. The coordinates of points P and Q are P(2, 3) and Q(6, 3) respectively. Using the distance formula, we have PQ = √((6-2)^2 + (3-3)^2) = √(16) = 4.