133k views
2 votes
Which expression is equivalent to the following complex tion?

[(y+1)(y-1)/2 ÷ y+1/y-1]

A. (y-1)/2)

B. (y+1/y-1)

C. (y-1/y+1)

D. (y+1)(y-1)/2)

User ItayM
by
8.0k points

1 Answer

1 vote

Final answer:

The equivalent expression to the given fraction [(y+1)(y-1)/2 ÷ (y+1)/(y-1)] is (y-1)/2 by canceling out common terms in the numerator and the denominator.

Step-by-step explanation:

To find the expression equivalent to the complex fraction [(y+1)(y-1)/2 ÷ (y+1)/(y-1)], we need to follow a step-by-step process. First, understand the operation: division of fractions is the same as multiplication by the reciprocal. So, re-write the expression by keeping the first fraction and multiplying by the reciprocal of the second:

[(y+1)(y-1)/2] × [(y-1)/(y+1)]

Next, simplify by canceling out terms that appear both in the numerator and the denominator. The terms (y+1) in the first fraction's numerator and the second fraction's denominator cancel each other out. Similarly, the (y-1) terms cancel out:

[(y-1)/2]

Therefore, the equivalent expression to the given complex fraction is option A: (y-1)/2.

User Carlosrafaelgn
by
7.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories