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If c(x 3) 2(x-1)=dx 4, find the values of constants c and d.

User SamV
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Final answer:

By expanding and simplifying the given equation, we find that the values of the constants are c = 2/3 and d = -4/3 by matching coefficients.

Step-by-step explanation:

The student has provided an equation that requires finding the values of the constants c and d. To do this, we need to expand and simplify the given equation c(x + 3) = 2(x - 1) + dx + 4. We'll expand both sides and collect like terms, matching the coefficients of the corresponding terms on each side of the equation.

First, expand the left side to get cx + 3c. Next, expand the right side to get 2x - 2 + dx + 4. Then combine like terms on the right side to give (2 + d)x + 2. Now, we have cx + 3c = (2 + d)x + 2. Matching coefficients, we get two equations: c = 2 + d and 3c = 2. Solving for c in the second equation, we get c = 2/3. Plugging this value into the first equation, we solve for d, yielding d = c - 2 = 2/3 - 2 = -4/3.

To find the values of constants c and d, we can start by expanding the given equation: c(x^3) + 2(x-1) = dx^4.

Next, distribute the c and 2 to each term: cx^3 + 2x - 2 = dx^4.

Now, rearrange the terms and set the equation equal to 0: dx^4 - cx^3 - 2x + 2 = 0.

By comparing the coefficients of like terms, we can set up a system of equations to solve for c and d. In this case, c = -2 and d = 1.

User Neil Sant Gat
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