Final answer:
Pump B has a higher variation in process time compared to Pump A.
Step-by-step explanation:
Pump A has a mean effective process time of 4 minutes with a squared-coefficient of variation of 0.5. This means that the standard deviation of Pump A's process time is equal to 0.5 times its mean, which is 0.5 * 4 = 2 minutes. Pump B, on the other hand, has a mean effective time of 3 minutes with a squared-coefficient of variation of 5. Therefore, the standard deviation of Pump B's process time is equal to 5 times its mean, which is 5 * 3 = 15 minutes. So, Pump B has a higher variation in process time compared to Pump A.