Question

5,000 6-cylinder connecting rods and 7,000 4-cylinder connecting rods. Let x₄ = the number of 4−cψlinder connecting rods produced next week xₑ= the number of 6 -cylinder connecting rads produced next week s₄ =1 if the production line is set up to produce the 4-cylinder cannecting rods; 0 ir athervise s₆ =1 if the production line is set up to praduce the 6 -cylinder cannecting rods; 0 if othervise. Using the decision variables x₄ and 5₄

, write a constraint that limits next week's production of the 4-cylinder connecting rods to either 0 or 7,000 units.

Answer 1

To constrain the production of 4-cylinder connecting rods to 0 or 7,000 units, a linear constraint x4 <= 7000 * s4 can be used, where x4 is the number of rods and s4 is a binary setup variable.

Step-by-step explanation:

The student is asking for help in formulating a linear constraint concerning the production of 4-cylinder connecting rods based on given decision variables. Using x₄ to represent the number of 4-cylinder connecting rods and s₄ as the binary setup variable, the constraint to ensure that next week's production is limited to either 0 or 7,000 units is:

x₄ ≤ 7000 * s₄

This constraint indicates that if the production line is set up for 4-cylinder connecting rods (s₄ = 1), then x₄ can be as many as 7,000 units. If not (s₄ = 0), then x₄ must be 0