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Construct on a single diagram, a triangle PQR; PQ=7cm, QR=8.2cm, angle Q=120∘. Locus of points that are 3.6cm from PQ and on the same side of PQ as R

A. Circle with center Q
B. Perpendicular bisector of PQ
C. Arc with center R
D. Parabola with focus P

User Tony Dong
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1 Answer

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Final answer:

To construct triangle PQR, draw line segments PQ and QR with their given lengths and angle. For the locus of points, draw arcs from points A and R and find their intersecting points on PQ. To construct a circle with center QB, draw a circle with its center at point Q and the radius equal to the length QB. For the perpendicular bisector of PQC, find the midpoint of PQ and draw a perpendicular line through it. For the arc with center RD, draw an arc with R as the center and RD as the radius. Note that additional information is needed to construct a parabola with focus P.

Step-by-step explanation:

To construct a triangle PQR, we will use the given measurements and angles. First, draw a line segment PQ with a length of 7cm. Then, measure an angle of 120 degrees at point Q. Next, draw a line segment QR with a length of 8.2cm, making sure it connects to point Q. You have now constructed triangle PQR.

To construct the locus of points that are 3.6cm from PQ and on the same side of PQ as RA, draw arcs with a radius of 3.6cm from points A and R. The points where these arcs intersect PQ will be the locus of points.

To construct a circle with center QB, draw a circle with a center at point Q and a radius of the length QB.

To construct the perpendicular bisector of PQC, find the midpoint of segment PQ and draw a line perpendicular to PQ through the midpoint.

To construct an arc with center RD, draw an arc with a center at point R and a radius of the length RD.

To construct a parabola with focus P, you will need additional information.

User Adam Duro
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