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Thru (6,5) parallel to 4x−3y=π. Write in standard form.

A. 4x−3y=π+30
B. 4x−3y=π−30
C. 4x−3y=30−π
D. 4x−3y=π−5

User Allcaps
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1 Answer

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Final answer:

The question sought the equation of a line parallel to 4x-3y=π, passing through (6,5). It can be derived that its standard form is 4x-3y=c, where c is a real number, which isn't matching the provided answer options exactly.

Step-by-step explanation:

The student has asked to find the equation of a line that passes through the point (6,5) and is parallel to the line represented by 4x−3y=π (in standard form). Parallel lines have the same slope. Therefore, the new line will also have the form 4x−3y=b for some value b. To find b, you substitute the coordinates of the given point into this equation: 4(6) - 3(5) = b, which simplifies to 24 - 15 = b, thus b = 9. However, since the original line's equation is 4x−3y=π, b must be expressed in terms of π. As π + 9 differs from the options provided, the closest correct choice would be to represent the line in the format '4x−3y=c', where c is any real number. Hence, the answer will not match the provided options exactly.

User Dan Roberts
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