Question

Factoring a Difference of Perfect Squares. The polynomial is a difference of perfect squares. Use the formula a^2−b^2=(a+b)(a−b) to factor completely.

8132−498132−49

A. The value of a is 8787.
B. The value of b is 66.
C. The product of the prime factors is 3×293×29.
D. The value of a is 8282.

Answer 1

To factor the given polynomial, we can use the formula a^2 − b^2 = (a + b)(a - b). Substituting the given values of a and b into the formula, we can simplify the expression and obtain the factored form of the polynomial.

Step-by-step explanation:

To factor the polynomial using the formula a^2 − b^2 = (a + b)(a - b), we need to identify the values of a and b. In this case, a is 8132 and b is 49. Substituting these values into the formula, we get:

8132^2 − 49^2 = (8132 + 49)(8132 - 49)

Simplifying the equation further:

(8181)(8083)

So, the factored form of the polynomial is (8132 + 49)(8132 - 49) = (8181)(8083).