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4 votes
If f(1)=160 and f(n+1)=−2f(n), what is f(4)?
A. 640
B. -1280
C. 2560
D. -5120

User Yaron Levi
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2 Answers

4 votes

Answer:

f(1) = 160

f(2) = -2f(1) = -2(160) = -320

f(3) = -2f(2) = -2(-320) = 640

f(4) = -2f(3) = -2(640) = -1,280

The correct answer is B.

User Cogle
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7.4k points
4 votes

Final answer:

To find f(4), we can start by finding the value of f(2) and f(3) using the given equation. Using the equation f(n+1) = -2f(n), we can find f(2) = -320 and f(3) = 640. Finally, plugging in n=3 gives us f(4) = -1280.

Step-by-step explanation:

To find f(4), we can start by finding the value of f(2) and f(3) using the given equation. Since f(n+1) = -2f(n), we can find f(2) by plugging in n=1, which gives us f(2) = -2f(1) = -2*160 = -320. Similarly, we can find f(3) by plugging in n=2, which gives us f(3) = -2f(2) = -2*(-320) = 640. Finally, we can find f(4) by plugging in n=3, which gives us f(4) = -2f(3) = -2*640 = -1280.

User Mike De Klerk
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7.9k points