Final answer:
The oxidation half-reaction for the given equation is B) Zn(s) → Zn2+(aq) + 2e−, representing the loss of electrons as zinc is oxidized to Zn2+.
Step-by-step explanation:
The oxidation half-reaction that correctly describes the oxidation occurring in the reaction Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g) is B) Zn(s) → Zn2+(aq) + 2e−. In a redox reaction, the substance that loses electrons is said to be oxidized. Here, zinc atoms are oxidized to Zn2+, showing a loss of two electrons which are then written as products, transforming neutral zinc into a 2+ ion.
In the provided reaction, zinc acts as the reductant as it loses electrons during the reaction. This process of zinc losing electrons corresponds to the half-equation Zn(s) → Zn2+(aq) + 2e−. It's important to note that the overall charge is balanced on both sides of the half-reaction.