Question

Consider the combustion of butane: 2C4H10(g) + 13O2(g) = 8CO2(g) + 10H2O(1). If you have 50.0 grams of butane, how many moles of butane do you have? (Atomic weights: C = 12.01 g/mole, H = 1.01 g/mole, O = 16.00 g/mole)

a. 1.39 moles
b. 2.77 moles
c. 3.33 moles
d. 4.17 moles

Answer 1

To calculate the number of moles of butane, divide the mass of butane by its molar mass. In this case, 50.0 grams of butane is equal to approximately 0.8619 moles.

Step-by-step explanation:

To calculate the number of moles of butane, we need to use the molar mass of butane. The molar mass of C4H10 can be calculated by adding the molar masses of carbon (C) and hydrogen (H):

Molar mass of C4H10 = (4 * atomic mass of C) + (10 * atomic mass of H)

= (4 * 12.01 g/mol) + (10 * 1.008 g/mol)

= 48.04 g/mol + 10.08 g/mol

= 58.12 g/mol

Now, we can calculate the number of moles of butane using the given mass of 50.0 grams:

Number of moles of butane = mass of butane / molar mass of butane

= 50.0 g / 58.12 g/mol

= 0.8619 mol