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The half-life of a 100 gram of Au-198 is 2.3 days. (a) Find the decay constant k. (Write the answer in the exact form or in 5 decimal places)

User Orangutech
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Final answer:

The decay constant k for Au-198 with a half-life of 2.3 days is calculated using the formula k = ln(2) / t1/2, resulting in a value expressed either in exact form or in five decimal places.

Step-by-step explanation:

To find the decay constant k for Au-198 with a half-life of 2.3 days, we use the formula that relates the decay constant to the half-life:

k = ln(2) / t₁/₂

Where ln(2) is the natural logarithm of 2 (approximately equal to 0.693) and t₁/₂ is the half-life.

Therefore, we have:

k = ln(2) / 2.3 days

This calculation gives us the value of k in days⁻¹. In order to make it more accurate, we'll express the answer in five decimal places if not in exact form.

Note: The unit for time (days) is included to indicate that this is how k should be interpreted when using it in further calculations.

User Aseidma
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