Question

Solve the right triangle shown in the figure to the right. Round lengths to two decimal places and express angles to the nearest tenth of a degree.

A=33.1°, b=32
B=0°

Answer 1

To solve the given right triangle with angle A = 33.1°, side b = 32, and angle B = 0°, we can use the sine and cosine ratios. Using these ratios, we can find the lengths of sides a and c, and the value of angle C.

Step-by-step explanation:

In the given right triangle, we are given the angle A = 33.1°, side b = 32, and angle B = 0°. To solve the triangle, we can use the sine and cosine ratios.

1. Using the sine ratio, sin(A) = opposite/hypotenuse, we can find the length of side a: a = b*sin(A) = 32*sin(33.1°).
2. Using the cosine ratio, cos(A) = adjacent/hypotenuse, we can find the length of side c: c = b*cos(A) = 32*cos(33.1°).
3. To find angle C, we can use the fact that the sum of angles in a triangle is 180°. Angle C = 180° - A - B = 180° - 33.1° - 0°.

Using these calculations, we can solve the right triangle and find the values for sides a, b, and c, and angles A, B, and C.