Question

Calculate the potential difference maintained between two horizontal conductors separated by a distance of 10 mm so that a small charged drop of mass 1.31 x 10 kg will remain in its place. Charge in the oil drop is 6.4 x 10^-19 C.

a. (1.38 × 10⁻⁶) V

b. (2.76 × 10⁻⁶) V

c. (4.56 × 10⁻⁶) V

d. (6.82 × 10⁻⁶) V

Answer 1

To calculate the potential difference between two horizontal conductors, use the equation V = Q / d, where V is the potential difference, Q is the charge, and d is the distance between the conductors. Plugging in the given values of Q = 6.4 x 10^-19 C and d = 10 mm = 0.01 m, we find the potential difference to be approximately 6.4 x 10^-17 V.

Step-by-step explanation:

To calculate the potential difference maintained between two horizontal conductors, we can use the equation:

V = Q / d

where V is the potential difference, Q is the charge, and d is the distance between the conductors.

Plugging in the given values: Q = 6.4 x 10-19 C and d = 10 mm = 0.01 m, we get:

V = (6.4 x 10-19 C) / (0.01 m) = 6.4 x 10-17 V

Therefore, the potential difference maintained between the two conductors is approximately 6.4 x 10-17 V.