Question

A certain city has one chance in two of receiving rain on June 1, one chance in five of receiving rain on July 1, and two chances in three of receiving rain on August 1. What is the probability that the city will receive rain on all of these days?

a. 1/15
b. 1
c. 2/15
d. 4/45

Answer 1

The probability that the city will receive rain on all three days is 1/15.

Step-by-step explanation:

The probability of an event happening is calculated by multiplying the individual probabilities of each event happening together. In this case, the city has a 1/2 chance of receiving rain on June 1, a 1/5 chance on July 1, and a 2/3 chance on August 1.

So, the probability of rain on all three days is (1/2) * (1/5) * (2/3) = 1/15.

Therefore, option a. 1/15 is the correct answer.