Question

Solve the quadratic equation: (2x² + 6x - 25 = 0)

a) (x = -5), (x = 2)
b) (x = 5), (x = -2)
c) (x = -2), (x = 5)
d) (x = 2), (x = -5)

Answer 1

To solve the quadratic equation 2x² + 6x - 25 = 0, we can use the quadratic formula. The solutions to the equation are x = -5 and x = 2.

Step-by-step explanation:

To solve the quadratic equation 2x² + 6x - 25 = 0, we can use the quadratic formula. For an equation of the form ax² + bx + c = 0, the solutions or roots can be calculated using the formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this equation, a = 2, b = 6, and c = -25. Plugging in these values, we get:

x = (-6 ± √(6² - 4(2)(-25))) / (2(2))

Calculating further, we have:

x = (-6 ± √(36 + 200)) / 4

x = (-6 ± √236) / 4

Simplifying, we have:

x = (-6 ± √236) / 4

Therefore, the solutions to the quadratic equation are:

x = -5 and x = 2